7
Süd / alle
D975
B83
DB7
1097
B3
AD9652
96
AKB
7
S
AK62
74
K532
D63
O/W 4 =
1084
K10
A1084
8542
SA
N
S
O33423
W22422
Paar IMPIMPNSKontraktAussp.ErgebnisOWIMPPaar IMP
−1,001O 3SA =3      60010701,0
−2,002W 3SA +110      63010802,0
−2,005W 4 =D      62010302,0
12,0126O 3SA -18100      104−12−12,0
−1,007O 3SA =8      60010101,0
−2,008W 4 =D      62010202,0
−2,003W 4 =D      62010502,0
−2,0−124W 4 =D      620106122,0