24
West / -
10754
9532
3
A1076
K8
A876
KB72
K94
W24
B92
KB10
A9654
D8
O/W 3SA =
O/W 5 =
AD63
D4
D108
B532
SA
N11
S11
O533
W533
Paar IMPIMPNSKontraktAussp.ErgebnisOWIMPPaar IMP
4,001O 3SA -1350      1050−4,0
−7,40208W 3SA +14      43030407,4
−7,0−102O 3SA =6      400106107,0
5,92207W 5 -2A100      203−2−5,9
4,005W 3SA -1650      1010−4,0
−7,40204W 3SA +14      43010807,4
4,0106W 3SA -1750      102−10−4,0
4,0−2103W 3SA -1650      1072−4,0