1
Nord / -
D103
1082
D8754
75
B92
KD75
A1062
103
N
1
876
A
KB93
ADB84
O/W 2SA =
AK54
B9643
K962
SA
N1
S1
O1212
W122
Paar IMPIMPNSKontraktAussp.ErgebnisOWIMPPaar IMP
4,961O 4 -2A100      107−6−4,9
3,102O 3 -1A50      1080−3,1
−9,0−85W 3SA +12      43010389,0
−2,3−56W 2SA +12      15010452,3
−2,0−67O 2 +2A      13010162,0
3,108O 3 -1A50      1020−3,1
−1,083O 3 =A      110105−81,0
3,154W 3SA -1250      106−5−3,1