22
Ost / OW
A64
8752
K32
1073
B1072
B93
D8
D942
22O
D93
AK6
A10654
B6
O 2 =
K85
D104
B97
AK85
SA
N1
S1
O1121
W11
Paar IMPIMPNSKontraktAussp.ErgebnisOWIMPPaar IMP
3,36201O 1SA -15100      3−6−3,3
−4,0−1502N 2 -3B      15010414,0
−2,1−9105O 1SA =5      9010792,1
−2,1−5406N 1 -2B      10030852,1
−3,1−6203O 1SA +1A      12030163,1
−3,114O 1SA +1A      120602−13,1
8,097O 3 -3A300      5−9−8,0
3,35108N 2 =B110      206−5−3,3